D-Link Forums
The Graveyard - Products No Longer Supported => Routers / COVR => DIR-615 => Topic started by: jan.renzlow on July 25, 2014, 09:59:21 AM
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Hallo,
my network is organized like this
ISP -> cable modem -> DIR 615 Rev. H -> LAN with PCs
IP of my Cable-Modem 192.168.0.100
IP od Dir-615 Rev. H 192.168.2.1 Subnet Mask 255.255.255.0
How can I configure my routing table in http://192.168.2.1/adv_routing.htm to get direct access to the website of my cable modem?
I've an idea - but I'm not really sure. This is the reason for this question.
Thanks for your answer in advance.
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- Link>What Firmware (http://forums.dlink.com/index.php?topic=47512.0) version is currently loaded? Found on the routers web page under status.
- What region are you located?
Internet Service Provider and Modem Configurations
- What ISP Modem Mfr. and model # do you have?
- Is ISP Modem/Service using Dynamic or Static WAN IP addressing?
- What ISP Modem service link speeds UP and Down do you have?
- If the ISP modem has a built in router, it's best to bridge the modem. Having 2 routers on the same line can cause connection problems: Link>Double NAT (http://www.practicallynetworked.com/networking/fixing_double_nat.htm) and How NAT Works (http://cognitiveanomalies.com/cisco-nat-how-nat-works/). To tell if the modem is bridged or not, look at the routers web page, Status/Device Info/Wan Section, if there is a 192.168.0.# address in the WAN IP address field, then the modem is not bridged. If the modem can't be bridged then see if the modem has a DMZ option and input the IP address the router gets from the modem and put that into the modems DMZ.
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Any status on this? ???
Hallo,
my network is organized like this
ISP -> cable modem -> DIR 615 Rev. H -> LAN with PCs
IP of my Cable-Modem 192.168.0.100
IP od Dir-615 Rev. H 192.168.2.1 Subnet Mask 255.255.255.0
How can I configure my routing table in http://192.168.2.1/adv_routing.htm to get direct access to the website of my cable modem?
I've an idea - but I'm not really sure. This is the reason for this question.
Thanks for your answer in advance.